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fair In other words, when we use FEC, fairness in the MAC layer does not translate to the desired fairness in the application layer Therefore, wireless fair scheduling algorithms must keep track of the actual throughput and update the lag or the lead of flows accordingly FEC schemes can improve channel capacity utilization in the absence of perfect channel state information The MAC layer can include additional redundancy in the packet to be transmitted, resulting in increased number of successful transmissions There is a tradeoff between the robustness and the loss of channel capacity due to this additional redundancy In [7], an adaptive control algorithm is proposed to optimize the gain in the channel capacity by using varying degrees of redundancy in the transmitted packet This algorithm can be used in conjunction with any wireless scheduling algorithm to obtain better performance We believe that this area needs further investigation 8.

Everything worth doing encounters resistance along the way. To move a big rock requires you to ght gravity and inertia. To climb a mountain requires you to overcome the effects of thin air. Say, for instance, you return from giving a presentation to a potential partner. The discussions went well and you feel the prospect should be doing business with you and not your competitor. But one person in the meeting announced to the room that the company doesn t have room in its budget this year. What is your attitude when you hear this What is your disposition to obstacles In 1905, Madam C. J. Walker started selling a scalp conditioning and healing formula, Madam Walker s Wonderful Hair Grower, door-to-door to African-American women throughout the South and Southeastern United States. Walker, the daughter of former slaves, had been orphaned at age 7, married at 14, and widowed with a child at 19. She worked doing laundry to put her daughter through school before she envisioned a new life for herself. I got my start by giving myself a

53 Scheduling in Multihop Wireless (Ad Hoc) Networks In ad hoc networks, mobile hosts are distributed over a given area, where each mobile host is not always within range of all hosts Communication between two hosts is done by a series of hops between neighboring nodes Such networks are characterized by the absence of a coordinating host, and as a result, no host has global information A simple example of such a network is shown in Figure 83 In this figure, host D can hear hosts A, B, C, and E, whereas host F can hear only host E Thus, D has to contend for channel access among its four neighbors, while F has only one contending neighbor.

X.25 deals primarily with which OSI layer and LAPB How does a processor know where a frame s eld boundaries are Where is an X.25 DTE located its DCE located

If we assume that each host obtains a bandwidth share that is inversely proportional to the number of hosts within its range, then D gets one-fifth of the channel capacity, whereas F gets half of the capacity The channel share is dependent on the location of the host Another way of assigning the channel bandwidth is to consider flows, ie, pairs of communicating nodes, and divide the bandwidth among flows in a.

with a unit sum. The vector W forms a weighted average type aggregating operator with exponentially decreasing weights that depend on a. The key question in EWMA application is the memory depth (moving window length) of the aggregating operator. It can be shown that the memory depth Ka is approximately reciprocal to the forgetting factor Ka 1/a. The moving window length is calculated for indexes belonging to the soft interval: s 2 fk Ka 1; k 12:28

Singular value: The singular values of an (m x n) matrix A are the nonnegative square roots of the eigenvalues of AA H , if m n, and of AH A, if m 2: n. (See Sect.ions 5.1 and 5.5.)

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